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-0.01x^2-24x-180=0
a = -0.01; b = -24; c = -180;
Δ = b2-4ac
Δ = -242-4·(-0.01)·(-180)
Δ = 568.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-\sqrt{568.8}}{2*-0.01}=\frac{24-\sqrt{568.8}}{-0.02} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+\sqrt{568.8}}{2*-0.01}=\frac{24+\sqrt{568.8}}{-0.02} $
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